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🔢 Real Numbers • Lesson 17

Bounds and Error Intervals

Learn how rounded measurements represent a range of possible values and how to calculate lower bounds, upper bounds and error intervals.

🔢 Real Numbers ✏️ Worked examples included 🧠 Step-by-step learning

🎬 See the interval around a rounded value

A rounded value represents every original value inside its error interval.

🎯 By the end of this lesson...

You should be able to:

🤔 Think About This...

⚖️

Is the bag exactly 2 kilograms?

A bag of sugar is labelled:

2 kg

Does the bag have a mass of exactly 2.000000 kg?

Its actual mass could instead be:

  • 1.998 kg;
  • 2.001 kg;
  • 2.003 kg.

The value shown on the label may have been rounded.

A rounded measurement represents a range of possible actual values, rather than only one exact value.

1️⃣ Exact Values and Measured Values

Exact values

Exact values are normally obtained by counting.

12 eggs 30 learners 8 books 5 chairs

There is no rounding uncertainty.

Measured values

Measured values are obtained using instruments.

1.7 m 35°C 4.6 kg 12.3 cm

The displayed value may have been rounded.

Counting usually gives exact values. Measuring usually gives approximations because measuring instruments have limited precision.

💡 Did You Know?

Even highly accurate scientific instruments have limits.

Scientists and engineers therefore record the range within which the actual value is expected to lie.

🏗️ Construction
⚙️ Manufacturing
🌡️ Temperature
🧪 Scientific experiments
🧁 Food measurement
🛣️ Road distances

2️⃣ What Is a Bound?

A bound describes the smallest or largest possible actual value represented by a rounded measurement.

Lower bound

The smallest possible value that would round to the stated measurement.

Upper bound

The value at which the measurement would begin rounding to the next number.

Example 1: A length is 15 cm to the nearest centimetre

Values from 14.5 cm up to, but not including, 15.5 cm round to 15 cm.

14.5 Lower bound
15 cm
15.5 Upper bound
Lower bound = 14.5 cm

Upper bound = 15.5 cm

3️⃣ The Half-Unit Rule

To find bounds, first identify the unit used for rounding.

Then find half of that unit.

Rounded to the nearest... Rounding unit Half of the unit
10 10 5
Whole number 1 0.5
One decimal place 0.1 0.05
Two decimal places 0.01 0.005
Three decimal places 0.001 0.0005

Lower bound

Rounded value − half the rounding unit

Upper bound

Rounded value + half the rounding unit

🧠 StudyNest Method: Finding Bounds

Step 1: Identify the place value or unit to which the number was rounded.

Step 2: Find half of that rounding unit.

Step 3: Subtract the half-unit from the rounded value to find the lower bound.

Step 4: Add the half-unit to the rounded value to find the upper bound.

Step 5: Write the error interval using:

lower bound ≤ actual value < upper bound
Half below → Rounded value → Half above

4️⃣ Bounds to the Nearest Whole Number

Example 2: A mass is 40 kg to the nearest kilogram

The rounding unit is 1 kg.

Half of 1 kg = 0.5 kg

Lower bound

40 − 0.5 = 39.5

Upper bound

40 + 0.5 = 40.5
Lower bound = 39.5 kg

Upper bound = 40.5 kg

Example 3: A distance is 126 m to the nearest metre

Half of 1 m = 0.5 m
Lower bound = 126 − 0.5 = 125.5
Upper bound = 126 + 0.5 = 126.5
125.5 m ≤ actual distance < 126.5 m

5️⃣ Bounds to One Decimal Place

Example 4: A distance is 3.6 km to one decimal place

One decimal place means the number was rounded to the nearest 0.1.

Half of 0.1 = 0.05
Lower bound = 3.6 − 0.05 = 3.55
Upper bound = 3.6 + 0.05 = 3.65
3.55 km ≤ actual distance < 3.65 km

Example 5: A temperature is 28.4°C to one decimal place

Half of 0.1°C = 0.05°C
Lower bound = 28.4 − 0.05 = 28.35
Upper bound = 28.4 + 0.05 = 28.45
28.35°C ≤ actual temperature < 28.45°C

6️⃣ Bounds to Two Decimal Places

Example 6: A height is 1.72 m to two decimal places

Two decimal places means the number was rounded to the nearest 0.01 m.

Half of 0.01 = 0.005
Lower bound = 1.72 − 0.005 = 1.715
Upper bound = 1.72 + 0.005 = 1.725
1.715 m ≤ actual height < 1.725 m
The bounds normally contain one more decimal place than the rounded value.

7️⃣ Bounds to the Nearest Ten

Example 7: A crowd is estimated as 480 people to the nearest ten

The rounding unit is 10.

Half of 10 = 5
Lower bound = 480 − 5 = 475
Upper bound = 480 + 5 = 485
475 ≤ actual number of people < 485
Do not automatically use 0.5. The half-unit depends on what the value was rounded to.

8️⃣ Writing Error Intervals

An error interval shows the complete range of possible values.

Lower bound ≤ x < Upper bound

Example 8: A length is 20 cm to the nearest centimetre

Lower bound = 19.5 cm
Upper bound = 20.5 cm
19.5 ≤ x < 20.5

9️⃣ Why Is the Upper Bound Not Included?

Consider a value recorded as 20 to the nearest whole number.

20.49

This rounds down to 20.

Included

20.50

This rounds up to 21.

Not included
19.5 ≤ x < 20.5
Writing 19.5 ≤ x ≤ 20.5 is incorrect because 20.5 does not round to 20.

🔍 Inequality Symbols in Error Intervals

Less than or equal to

The lower bound is included.

<

Less than

The upper bound is not included.

Use at the lower end and < at the upper end.

🔟 Finding the Rounded Value from an Error Interval

Example 9

12.5 ≤ m < 13.5

The midpoint of the interval is:

(12.5 + 13.5) ÷ 2 = 13

The interval has a width of 1, so the measurement was rounded to the nearest whole number.

The recorded measurement was 13, correct to the nearest whole number.

🌍 Real-Life Example: Carpentry

Example 10

A carpenter records the length of a wooden plank as 2.4 m, correct to the nearest 0.1 m.

Half of 0.1 m = 0.05 m
Lower bound = 2.4 − 0.05 = 2.35
Upper bound = 2.4 + 0.05 = 2.45
2.35 m ≤ actual length < 2.45 m
This range matters when parts must fit together accurately.

🌍 Real-Life Example: Road Distance

Example 11

A road distance is recorded as 4.8 km, correct to the nearest 0.1 km.

Lower bound = 4.8 − 0.05 = 4.75
Upper bound = 4.8 + 0.05 = 4.85
4.75 km ≤ actual distance < 4.85 km

🌍 Real-Life Example: Package Mass

Example 12

The mass of a parcel is recorded as 6.35 kg, correct to the nearest 0.01 kg.

Half of 0.01 kg = 0.005 kg
Lower bound = 6.35 − 0.005 = 6.345
Upper bound = 6.35 + 0.005 = 6.355
6.345 kg ≤ actual mass < 6.355 kg

🧠 The StudyNest Bounds Strategy

Step 1: Read what the value was rounded to.

Step 2: Write the rounding unit.

Step 3: Divide the rounding unit by 2.

Step 4: Subtract that amount for the lower bound.

Step 5: Add that amount for the upper bound.

Step 6: Write the interval as:

lower bound ≤ value < upper bound

Step 7: Include the correct measurement units.

🎯 Exam Tips

Identify the rounding unit before beginning any calculation.
The adjustment is half the rounding unit, not the complete rounding unit.
The lower bound is included, while the upper bound is excluded.
Bounds usually contain one more decimal place than the rounded value.
Keep measurement units consistent throughout the calculation.
Check that the original rounded value lies halfway between the two bounds.

⚠ Common Mistakes

Mistake 1:

Adding and subtracting the full rounding unit instead of half of it.
Mistake 2:

Assuming every whole number has bounds 0.5 away without checking whether it was rounded to the nearest ten, hundred or another unit.
Mistake 3:

Including the upper bound using ≤.
Mistake 4:

Using 0.5 instead of 0.05 for a value rounded to one decimal place.
Mistake 5:

Confusing the lower and upper bounds.
Mistake 6:

Forgetting measurement units in the final answer.
Mistake 7:

Treating a counted quantity as though it were a rounded measurement.

🎮 Your Turn!

🟢 Foundation Questions

  1. State whether each value is exact or measured:

    a) 18 learners
    b) 1.6 metres
  2. Find the lower and upper bounds of 15 kg, correct to the nearest kilogram.
  3. Find the lower and upper bounds of 28 cm, correct to the nearest centimetre.
  4. Write the error interval for 42 m, correct to the nearest metre.
  5. Find the bounds of 350, correct to the nearest ten.
  6. Find the bounds of 7200, correct to the nearest hundred.

🔵 Developing Questions

  1. Find the lower and upper bounds of 5.8 kg, correct to one decimal place.
  2. Find the bounds of 16.42 cm, correct to two decimal places.
  3. Write the error interval for 7.3 litres, correct to one decimal place.
  4. Write the error interval for 2.68 metres, correct to two decimal places.
  5. A temperature is recorded as 31.6°C, correct to one decimal place. Find its error interval.
  6. A package has a recorded mass of 4.25 kg, correct to the nearest 0.01 kg. Find its bounds.

🔴 Challenge Questions

  1. A road is recorded as 4.8 km long, correct to the nearest 0.1 km. Find its lower bound, upper bound and error interval.
  2. The length of a field is recorded as 120 m, correct to the nearest 10 m. Write its error interval.
  3. The error interval for a mass is:

    17.5 ≤ m < 18.5

    State the recorded mass and the degree of accuracy.
  4. The error interval for a length is:

    6.25 ≤ x < 6.35

    State the recorded length and the unit to which it was rounded.
  5. A student writes the following interval for 12.4 cm, correct to one decimal place:

    12.35 ≤ x ≤ 12.45

    Explain the mistake and write the correct interval.
  6. A package is labelled 3 kg, correct to the nearest kilogram. Could its actual mass be:

    a) 2.51 kg?
    b) 3.49 kg?
    c) 3.50 kg?
✅ Show Answers
  1. a) Exact

    b) Measured
  2. Lower bound = 14.5 kg

    Upper bound = 15.5 kg
  3. Lower bound = 27.5 cm

    Upper bound = 28.5 cm
  4. 41.5 ≤ x < 42.5
  5. Rounded to nearest 10:

    Half-unit = 5

    345 ≤ x < 355
  6. Rounded to nearest 100:

    Half-unit = 50

    7150 ≤ x < 7250
  7. Half of 0.1 = 0.05

    Lower bound = 5.75 kg

    Upper bound = 5.85 kg
  8. Half of 0.01 = 0.005

    Lower bound = 16.415 cm

    Upper bound = 16.425 cm
  9. 7.25 ≤ x < 7.35
  10. 2.675 ≤ x < 2.685
  11. 31.55°C ≤ t < 31.65°C
  12. 4.245 kg ≤ m < 4.255 kg
  13. Lower bound = 4.75 km

    Upper bound = 4.85 km

    4.75 ≤ d < 4.85
  14. Half of 10 m = 5 m

    115 m ≤ length < 125 m
  15. Recorded mass = 18

    Rounded to the nearest whole unit.
  16. The midpoint is:

    (6.25 + 6.35) ÷ 2 = 6.30

    The interval width is 0.10, so it was rounded to the nearest 0.1.

    Recorded length = 6.3
  17. The upper bound must not be included.

    Correct interval:

    12.35 ≤ x < 12.45
  18. The valid range is:

    2.5 ≤ m < 3.5

    a) Yes

    b) Yes

    c) No

🧠 Remember This

Counted values are usually exact.

Measured values may have been rounded.

Find half of the rounding unit.

Lower bound = rounded value − half-unit.

Upper bound = rounded value + half-unit.

Write error intervals as:

Lower bound ≤ actual value < upper bound.

The upper bound is not included.

🎯 Before Moving On...

🎉 Well Done!

You can now calculate bounds and describe the complete range represented by a rounded measurement.

Remember:

Identify the rounding unit → Find half → Subtract for the lower bound → Add for the upper bound → Write the interval

📈 Your Progress

Lesson 17

Real Numbers Progress 89%