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GRAPHS Β· LESSON 08

Quadratic Graphs

Explore smooth parabolas, roots, turning points and graphical solutions.

⏱️ 18–20 min πŸ“˜ Developing ✏️ Worked examples included

Learning Objectives

Introduction

This lesson develops Quadratic Graphs from meaning and patterns before moving to calculations. Look for what the quantities, shapes or symbols represent, then connect that idea to the method.

Key Notes

Read the definitions and key facts below carefully. Each rule is most useful when you can explain why it fits the situation, not simply recall it.

πŸ€” Think About This...

A ball thrown into the air rises, slows down, reaches a highest point and then falls.

Would its height against time form a straight line?

No. The rate of change is not constant, so the graph curves.

βˆͺ

Change the Quadratic

Adjust the coefficient and constant to see how the parabola responds.

What Is a Quadratic Graph?

A quadratic function contains an xΒ² term. Its graph is called a parabola.

y = xΒ² βˆ’ 4
xβˆ’3βˆ’2βˆ’10123
y50βˆ’3βˆ’4βˆ’305
A quadratic graph is smooth and curved. Do not join its points using separate straight line segments.

Important Features

Roots

Where the graph crosses the x-axis. At these points, y = 0.

y-intercept

Where x = 0.

Turning point

The lowest or highest point of the curve.

Axis of symmetry

A vertical line dividing the parabola into matching halves.

Worked Example: Reading Roots

The graph of y = xΒ² βˆ’ 4 crosses the x-axis at x = βˆ’2 and x = 2.

1

At an x-intercept, y = 0.

2

Therefore xΒ² βˆ’ 4 = 0.

3

The graph shows the solutions x = βˆ’2 and x = 2.

Solving Equations Graphically

To solve xΒ² βˆ’ 4 = 3, find where the graph y = xΒ² βˆ’ 4 has height y = 3.

  1. Draw or imagine the horizontal line y = 3.
  2. Read the x-coordinates where it meets the parabola.
  3. Those x-values solve the equation.
Graphical solutions are usually approximate. Read values to a sensible degree of accuracy.

βœ… Quick Check

What shape is a quadratic graph?
What is true about y at a root?
Find y when x = βˆ’2 for y = xΒ² + x βˆ’ 1.

🧠 Let’s Think Together

Before calculating, identify the information given, the result required and the mathematical relationship that connects them. Predict whether the answer should be larger, smaller or unchanged, then use that prediction to check the result.

Practice Questions

Foundation
  1. Complete a table for y = xΒ² βˆ’ 1 from x = βˆ’3 to x = 3.
  2. Plot the points and draw a smooth curve.
  3. Read the roots from your graph.
Developing
  1. Draw y = xΒ² βˆ’ 2x βˆ’ 3 for βˆ’2 ≀ x ≀ 4.
  2. Estimate the roots and turning point.
  3. Use the graph to solve xΒ² βˆ’ 2x βˆ’ 3 = 2.
Challenge
  1. Explain why the graph of y = βˆ’xΒ² + 4 opens downward.

βœ… Check Your Work

Attempt the questions before opening the solutions.

Show answers and working

Foundation

  1. For x=βˆ’3,βˆ’2,βˆ’1,0,1,2,3, y=8,3,0,βˆ’1,0,3,8.
  2. The points form a smooth U-shaped curve.
  3. The roots are x=βˆ’1 and x=1.

Developing

  1. For x=βˆ’2,βˆ’1,0,1,2,3,4, y=5,0,βˆ’3,βˆ’4,βˆ’3,0,5.
  2. Roots: x=βˆ’1 and x=3. Turning point: (1,βˆ’4).
  3. Solve xΒ²βˆ’2xβˆ’3=2, giving xΒ²βˆ’2xβˆ’5=0. Graphically xβ‰ˆβˆ’1.45 and xβ‰ˆ3.45.

Challenge

  1. The coefficient of xΒ² is negative, so y decreases away from its maximum and the parabola opens downward.

Common Mistakes

Exam Focus

Show the mathematical relationship you are using, keep notation consistent and give a clear final answer. Use a quick estimate, diagram or inverse operation to check that the result is reasonable.

Summary